2x^2-x-3=0

I got x=0 x=-3/2

Did i solve correctly?

Question

2x^2-x-3=0 

I got x=0  x=-3/2

Did i solve correctly?

anonymous · Answer

0 cannot be the solution I think..

anonymous · Answer

Put 0 back in the equation in place of x, you will not get 0...

ajprincess · Answer

I dnt thnk x=0 is right.
$2x^2-x-3=0$
$2x^2-3x+2x-3=0$
$x(2x-3)+1(2x-3)=0$
$(x+1)(2x-3)=0$
$x+1=0    ~or ~   2x-3=0$

anonymous · Answer

Getting @ursularoxursox

anonymous · Answer

i'm still having a difficult time understanding the equation

anonymous · Answer

i understand now. thanks for the help everyone!

ajprincess · Answer

welcome:)

ajprincess · Answer

If anythng is not clear plz ask:)

anonymous · Answer

I think I did another one wrong, can someone please guide me? 
The equation is 6x^2-5x-4=0

The first time I solved I got x=5/6  and x=-1
The second time I solved I got x=-1/6 and x=4
I don't think either are correct