Question

2x^2-x-3=0

I got x=0 x=-3/2

Did i solve correctly?

Answer 1

0 cannot be the solution I think..

Answer 2

Put 0 back in the equation in place of x, you will not get 0...

Answer 3

I dnt thnk x=0 is right.
\(2x^2-x-3=0\)
\(2x^2-3x+2x-3=0\)
\(x(2x-3)+1(2x-3)=0\)
\((x+1)(2x-3)=0\)
\(x+1=0 ~or ~ 2x-3=0\)

Answer 4

Getting @ursularoxursox

Answer 5

i'm still having a difficult time understanding the equation

Answer 6

i understand now. thanks for the help everyone!

Answer 7

welcome:)

Answer 8

If anythng is not clear plz ask:)

Answer 9

I think I did another one wrong, can someone please guide me?
The equation is 6x^2-5x-4=0

The first time I solved I got x=5/6 and x=-1
The second time I solved I got x=-1/6 and x=4
I don't think either are correct