Question

-10+log3(n+3)=-10

Answer 1

Is that log with a base of 3?

Answer 2

start by adding 10 to both sides

\[\log_{3}(n + 3) = 0\]

so using the fact that

\[3^{\log_{3}(a)} = a\]

then

\[n + 3 = 3^0\]

solve for n