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Precalculus 16 Online
OpenStudy (anonymous):

Rewrite with only sin x and cos x. sin 2x - cos x OPTIONS ARE 2 sin x cos2x sin x cos x (2 sin x - 1) 2 sin x

OpenStudy (cwrw238):

hint: use the identity sin2x = 2 sinx cosx

OpenStudy (anonymous):

how would i get the answer?

OpenStudy (anonymous):

so its A ? @cwrw238

OpenStudy (anonymous):

sin(x+x) = sinxcosx + cosxsinx = 2sinxcosx then sin 2x - cos x = 2sinxcox - cosx = cosx ( 2sinx - 1)

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