Question

Suppose sin A = 12/13 with 90º≤A≤180º. Suppose also that sin B = 7/25 with -90º≤B≤0º. Find tan (A - B).

Answer 1

find COS A = 1- SIN^2 (A), similarly COS B
then use tan(a-b)= TAN A - TAN B / (1+TAN A * TAN B)

Answer 2

okay thanks