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Simplify the radical expression. √39(√6+7) A. √45 + 7√39 B. 3√26 + 7√39 C. √234 + 7 D. √234 + 7√39 A, B, C, or D? Please explain (:
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\[B. 3\sqrt26+7\sqrt39\] \[(\sqrt{39})(\sqrt{6})+(\sqrt{39})(7)=(\sqrt{234})+7\sqrt{39}\] \[\sqrt{234}=\sqrt{3*3*26}=3\sqrt{26}\]
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