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Mathematics 16 Online
OpenStudy (anonymous):

Find the value of x when the gradient of the tangent is parallel to the x axis.

OpenStudy (anonymous):

\[y=(2x+3)^4\] at point (-1,1)

hartnn (hartnn):

know how to find gradient of tangent ?

OpenStudy (anonymous):

yup i got the equation of normal

OpenStudy (anonymous):

its \[y=\frac{ -x+7 }{ 8 }\]

hartnn (hartnn):

parallel to x-axis is horizontal line with slope (gradient) = 0 so u just need to differentiate y find dy/dx and put dy/dx =0

OpenStudy (anonymous):

hence x is equal to \[-\frac{ 3 }{ 2 }\] right?

hartnn (hartnn):

absolutely!

OpenStudy (anonymous):

great i got the answer thank you so much!

hartnn (hartnn):

welcome ^_^

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