Question

y2-9 5y
----- x ----
2y y-3

Answer 1

simplify (y^2 - 9) = (y+3)(y-3)
now just cancel out the common terms.

Answer 2

y^2-9 = (y+3)(y-3)

Answer 3

what about ?

s^2-2s s-5
--------- divided by -----
s^2+3s-10 s+5

Answer 4

for the fist numorator you can factor out one s so you get s(s-2)

Answer 5

then the equation will b like this just s+5 goes to numerator and s-5 in denominator

Answer 6

s^-2s = s(s-2)
s^2+3s-10 = (s+5)(s-2)
Now do it as I did the first problem...also use this a/b divided by c/d = ad/bc

Answer 7

for the denominator you need to find to varibles that add to 3 and multilpy to -10 which would be (s-2) and (s+5)

Answer 8

so is it s-2
-----
s-5 ?

Answer 9

you can simply this by concelling out some things

Answer 10

No..it should be s/s-5

Answer 11

sorry

Answer 12

therefor s-2 would cancel and s+5

Answer 13

im confused . so what is the answer ?

Answer 14

so answer s divided s-5

Answer 15

s/s-5

Answer 16

okay thanks!

Answer 17

: )