What are the approximate solutions of 4x2 + 3 = −12x to the nearest hundredth?

x ≈ −3.23 and x ≈ 0.23

x ≈ −2.72 and x ≈ −0.28

x ≈ 0.28 and x ≈ 2.72

x ≈ −0.23 and x ≈ 3.23

Question

What are the approximate solutions of 4x2 + 3 = −12x to the nearest hundredth? 

 x ≈ −3.23 and x ≈ 0.23 

 x ≈ −2.72 and x ≈ −0.28 

 x ≈ 0.28 and x ≈ 2.72 

 x ≈ −0.23 and x ≈ 3.23

tkhunny · Answer

The Quadratic Equation will lead you there.

anonymous · Answer

ok, can you show me how to do that?

tkhunny · Answer

Have you seen the Quadratic Formula?

anonymous · Answer

Well, yeah! But...

tkhunny · Answer

Okay, now rewrite the equation so it looks right: $4x^{2}+12x+3 = 0$

tkhunny · Answer

Note: I can see immediately that there is no Positive, Real solution.  This eliminates all but one possible answer.

anonymous · Answer

It's ok, I got the answer. :)