Mathematics
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OpenStudy (hba):
Equation of circle with center at (root(2),-3root(3) ) and radius 2 root (2)
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OpenStudy (hba):
No one answers here...Thank you.
OpenStudy (hba):
I am solving it .
OpenStudy (anonymous):
oh shush, mi trying to remember the circle equation
OpenStudy (anonymous):
You have done this earlier @hba
OpenStudy (anonymous):
\[(x-x_0)^2+y-y_0)^2=r^2\]
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OpenStudy (hba):
x^2+y^2+2root(2)x-6root(3)y+2root(2)=0 @waterineyes :D Right or wrong @hartnn Yes ?
OpenStudy (hba):
My radius is wrong lol :D
OpenStudy (anonymous):
Yes you have forgot to square it I guess..
OpenStudy (anonymous):
Also It will come to RHS..
OpenStudy (hba):
Wait i will do it again thanks :)
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OpenStudy (anonymous):
Equation is also wrong..
Everything is wrong.
Do it again.
ha ha ha..
OpenStudy (hba):
I know lol
ha ha ha
OpenStudy (anonymous):
Take your time..
OpenStudy (anonymous):
Sorry, take your time but solve it within 30 seconds..
Ha ha ha..
OpenStudy (hba):
I know that
x^2+y^2-2root(2) x +6 root(3) y +21=0
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OpenStudy (hba):
Here you go @waterineyes
OpenStudy (anonymous):
Where I go???
OpenStudy (anonymous):
Looking good to me..
OpenStudy (anonymous):
2 + 27 = 8
implies 21 on LHS..
OpenStudy (hba):
err....Right or wrong ?
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OpenStudy (anonymous):
Looking good means it is right..
Looking bad means it is absolutely right..
Okay??
Ha ha ha..
OpenStudy (hba):
Looks bad to me :)
OpenStudy (anonymous):
Well Done, you are right this time and now I am serious...