what is the cubic function of (1, -20), (7, -20), (2, -40), and (6, -40)

Question

tkhunny · Answer

ax^3 + bx^2 + cx + d = y
(1,-20)
a(1)^3 + b(1)^2 + c(1) + d = (-20)
(7,-20)
a(7)^3 + b(7)^2 + c(7) + d = (-20)
(2,-40)
a(2)^3 + b(2)^2 + c(2) + d = (-40)
(6,-40)
a(6)^3 + b(6)^2 + c(6) + d = (-40)

You have some solving to do.

anonymous · Answer

I'm dyslexic I don't understand the numbers mixed with letters

tkhunny · Answer

Well, then.  You're in a heap of trouble in algebra.  How did you get this far?

anonymous · Answer

Don't know

tkhunny · Answer

You're going to have to provide a hint of some kind.  Shall we use the brute-force algebra demonstrated above?  What class are you in?  What section are you studying?