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Mathematics 13 Online
OpenStudy (anonymous):

What is the range of y=-0.75x^2+0?

OpenStudy (tkhunny):

What's minimum possible valye for \(x^{2}\)?

OpenStudy (anonymous):

0 right?

OpenStudy (tkhunny):

And does this solve the problem?

OpenStudy (anonymous):

it makes y=0 and 0,0 is the vertex.

OpenStudy (tkhunny):

And the negative sign suggests [0,-∞)

OpenStudy (anonymous):

so it'd be \[y \le 0\] ?

OpenStudy (tkhunny):

Yes, that is another way to state it. Good call!

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