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What is the range of y=-0.75x^2+0?
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What's minimum possible valye for \(x^{2}\)?
0 right?
And does this solve the problem?
it makes y=0 and 0,0 is the vertex.
And the negative sign suggests [0,-∞)
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so it'd be \[y \le 0\] ?
Yes, that is another way to state it. Good call!
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