9.02] What are the solutions of 6x2 − x − 15 = 0? x = 5 over 6, x = −3 x = −5 over 6, x = 3 x = 3 over 2, x = −5 over 3 x = −3 over 2, x =5 over 3
Do you know how to use the quadratic formula?
Yeah, but I don't understand it, sorry about that!
Do you mind writing out the quadratic equation? I'll show you how to use it to solve this equation.
You still there?
Yep, I'm here! Ok, I will, wait a sec! :D
Just google; quadratic formula.
y = ax2 + bx + c
Um, that is not really correct. look at the attachment.
Can you view the attachment? If so, can you see the letters a, b, c? They are the ones that will get replaced with numbers from your equation: 6x2 − x − 15 = 0
Yep, I saw it, but the lesson put this.... A quadratic equation is an equation of the form y = ax2 + bx + c, where “a”, “b” and “c” are real numbers
Alright, then call this the quadratic formula.
Now replace the a with 6, the b with -1, and c with -15. Do you know where i got these numbers?
from the equation in the question.
yes.
Can you draw that out? with the letters replaced with the numbers that I posted above?
a with 6, the b with -1, and c with -15.
|dw:1353197500800:dw|
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