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y=1/2 x-1; (6,2), (0,1) show that each pair is a solution of the equation. then graph the two pairs to determine another solution.
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wow
replace \(x\) by \(6\) and \(y\) by \(2\) and see if it is true i.e. check that \[2=\frac{1}{2}\times 6-1\] if that is true (which it is) then \((6,2)\) is a "solution" to the equation
thank you . how would i find out about 0,1
repeat the process with \(x=0\) and \(y=1\)
for the 1/2 i devide that and get 0,5 right?
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