Question

x= -b +or- sq.root b sq. - 4ac all divided by 2a (sorry if this doesnt make sense)

Answer 1

thats quadratic formula

Answer 2

how do you solve it??

Answer 3

any specific question ?

Answer 4

Compare your quadratic equation with \(ax^2+bx+c=0\)
find a,b,c
then the two roots of x are:
\(\huge{x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)

Answer 5

oh ok i get it now, thanks

Answer 6

welcome ^_^