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Use the transformation u=x+y, v=x-y to evaluate the double integral...? Use the transformation u = x+y, v = x−y to evaluate ∫∫(R) of 4(x-y)e^(x+y)dA, where R is the square with vertices (0, 1), (1, 0), (2, 1) and (1, 2)
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i got 1<u<3 and -1<v<1 J=2 finally i got the answer is 0........
J=-1/2
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