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If cosc a =1/3t ,then tan a = ............. .
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cosec a=1/3t i.e sin a =3t hypotenuse=1 height=3t Find base with pythagoras. tan a = height/base.
...............................
?
srry, sin a=3t cos a=rt(1-9t^2) tan a=3t/rt(1-9t^2)
@Praja_01 Well you have done it right good going. :)
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Thanks a lot for your help @DLS
np :)
The answer is \[\tan a = \frac{ 3t }{ \ \sqrt{1-9t^2} }\]
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