Question

3x^2+27=0

Answer 1

3x^2 - 27 = 0
3 (x^2 - 9) = 0
3 (x-3)(x+3) = 0

x-3 = 0 or x+3 = 0
x = 3 or -3

-9x^2 + 12x = 0
-3x (3x - 4) = 0

3x = 0 or 3x-4 = 0
x = 0 or 4/3

Answer 2

ok @Jasminebunnies

Answer 3

Ohh I get it now! Thank you @mayankdevnani

Answer 4

welcome

Answer 5

@mayankdevnani the ques is 3x^2 + 27 = 0???????

Answer 6

i think the solution to this equation could not be determined @niksva 3x^2 + 27 = 0

sorry!! @Jasminebunnies

Answer 7

3x^2=-27
x^2=-9
x=sqrt-9

Answer 8

answer is \[x=\sqrt{-9}\]

Answer 9

3x^2 +27 = 0
3x^2 = -27
x^2 = -9
x = ± sqrt(-9)
x = ±3i

Answer 10

answer is x= ± 3i

Answer 11

yaa .. it can be...but definitely answer is the solution to this equation could not be determined

Answer 12

so the answer would be an imaginary number?

Answer 13

yeah solution would be an imaginary number

Answer 14

Oh ok thank you :)

Answer 15

right!!!