How many times is the blue light (blue photons) more energetic than the red light (red photons)?

Question

anonymous · Answer

Excellent latex work, @UnkleRhaukus ! :D

unklerhaukus · Answer

$$E=h\nu={hc}/\lambda$$

$$\lambda_{\color{red}{\text{red}}}\approx690[\text{nm}]$$$$\lambda_{\color{blue}{\text{blue}}}\approx460[\text{nm}]$$

$${E_{\color{blue}{\text{blue}}}}=n\times{E_{\color{red}{\text{red}}}}$$

unklerhaukus · Answer

$$n=\frac{E_{\color{blue}{\text{blue}}}}{E_{\color{red}{\text{red}}}}=\frac{hc/\lambda_{\color{blue}{\text{red}}}}{hc/\lambda_{\color{red}{\text{red}}}}=\frac{1/\lambda_{\color{blue}{\text{blue}}}}{1/\lambda_{\color{red}{\text{red}}}}=\frac{\lambda_{\color{red}{\text{red}}}}{\lambda_{\color{blue}{\text{blue}}}}$$