Question

Prove that x^4+x^2=1

Answer 1

whats x ?

Answer 2

variable :P

Answer 3

i mean is it cube root of unity ? or imaginary number i or something else ?
if not, then u just said its variable, so x^4+x^2 can't equal 1.

Answer 4

or do u need to solve for x ???

Answer 5

I don't know that is what I am trying to figure out... this was the question in my paper and I left it blank

Answer 6

just prove it to 1

Answer 7

by means of anything

Answer 8

good luck with that :)

Answer 9

what?

Answer 10

i think question is incomplete...we can solve for x, but can't prove that =1...

Answer 11

PROVE ???

Answer 12

x= 1 :P

Answer 13

nopes, x not =1 :P

Answer 14

then x= -1 :P

Answer 15

nopes, x not =-1 :P

Answer 16

x^4 +x^2=1 =>
=> x^4 +x^2 -1 = 0
=> (x +0.786)*(x -0.786)*(x^2 +1.618) = 0

Real solutions:
Root 1: -0.786
Root 2: 0.786
Complex roots:
Root 3: 0+1.272 * i
Root 4: 0-1.272 * i

Answer 17

are u solving that for x ,saura ?

Answer 18

there you go ^^

Answer 19

u copied that ^

Answer 20

yeah should i give the source ? :P

Answer 21

it is equal to 1

Answer 22

take a screenshot of your question

Answer 23

Looks like no solution