In the circuit shown below L=180.0H and C=2.25mF. The current source puts out an impulse of area A=2/π=0.64 Coulombs at time t=1.0s. At t=0 the state is: vC(0)=0.0 and iL(0)=1.0. The equation governing the evolution of the inductor current in this circuit is d2iL(t)dt2+1LCiL(t)=ALCδ(t−1.0) What is the natural frequency, in Hertz, of this circuit?

Question

In the circuit shown below L=180.0H and C=2.25mF. The current source puts out an impulse of area A=2/π=0.64 Coulombs at time t=1.0s.  At t=0 the state is: vC(0)=0.0 and iL(0)=1.0.  The equation governing the evolution of the inductor current in this circuit is  d2iL(t)dt2+1LCiL(t)=ALCδ(t−1.0)  What is the natural frequency, in Hertz, of this circuit?

anonymous · Answer

0.25009 Hz

anonymous · Answer

If you plug in your parameters on this wolfram calculator, it will calculate the resonant frequency for you. Just ensure that you type in the parameters 180H and 2.25mF in your problem correctly. http://www.wolframalpha.com/input/?i=resonance+frequency+2.25mF%2C+180H