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OpenStudy (anonymous):
1 + cos(6x) = ___? a. 2cos^2 (3x) b. 2sin^2 (3x) c. 3sin(2x) d. 3cos(2x)
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OpenStudy (nubeer):
cos2x =2cos^2x - 1 2cos^2(x) = 1+cos2x
OpenStudy (anonymous):
sin^2(3x)= 1-cos^2(3x) sin2x= 2sinx cosx cos2x=1- 2sin^2x
OpenStudy (raden):
i just continue what nubber said, hint : 1+cos2x = 2cos^2(x) change x be 3x to both sides :)
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