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Mathematics 21 Online
OpenStudy (anonymous):

What is the vertex of the parabola x = 5(y – 4)2 – 1 ?

OpenStudy (anonymous):

Please anyone, help. I know that the cordnites to the a vertex is (h,k) with : y = a(x – h)2 + k being the equation...

OpenStudy (anonymous):

Youre correct. SO since you know (h,k) is the vertex, apply that to your problem. Try to get your equation to be y=?

OpenStudy (anonymous):

It's sqrt((x+1)/5)+4 = y However, that doesn't fit with the (h,k) then

OpenStudy (anonymous):

gimme a sec plz

OpenStudy (anonymous):

since this is a "sidways" parabola, then your vertex is (k, h)

OpenStudy (anonymous):

So, (-1,4)?

OpenStudy (anonymous):

Thank you!

OpenStudy (anonymous):

lemme verify...

OpenStudy (anonymous):

yes.. that's right...:)

OpenStudy (anonymous):

yw...:)

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