Question

I need help finding an equation of the line that is parallel to the line 2x-3y=-4; containing the point (5,-3) please!!

Answer 1

Find the slope of 2x-3y=-4 by putting it into the y=mx+b form.
y=(2/3)x +(4/3)

Now you have the slope of 2/3 and a point (5,-3).
Can you find the new equation?

Answer 2

no.. the answer is \[y=\frac{ 2 }{3 }x +\frac{ 19 }{ 3 }\] but i don't understand where 19 came from

Answer 3

y=mx+b
-3=(2/3)(5)+b solve for b,
-3-(10/3)=b
-19/3=b

Answer 4

y=(2/3)x-(19/3)