In 1980, median family income was about $16,000, an in 2000 it was about $42,000. a) Find the slope of the line passing through the points (190,16000) and (2000, 42000). b) Intercept the slope as a rate of change. c) If this trend continues, estimate the median family income in 2003. Please help me and show me how to do this.
ok, just give me a minute
\[(190,16000) and (2000,42000)\]
this is your given slope, ok
then
\[P1(190,16000) P2(2000,42000) that is P=point \]
the formula for the slope or any slope is
y2-y1/x2-x1
then you just plug in those nubers
P1(190,16000) P2(2000,42000) x1 y1 x2 y2
y2-y1=42,000-16000 y2 y1
and x2-x1=2000-190 x2 x1
you subtract exactly what is on the equation
42,000-16000 is 41840 and 2000-190 is 1810
m=41840/1810 is m=32.11
this is your slope of the line
m=32.11
m=y2-y1/x2-x1 witch is m=42,000-16000/2000-190
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