Question

my last question, I'm stuck, Please help?
A set of 50 data values has a mean of 25 and a variance of 36.
I. Find the standard score (z) for a data value = 31.
II. Find the probability of a data value > 31.

Answer 1

\[\sigma ^{2}=36\]
\[\sigma=\sqrt{36}\]
\[z=\frac{X-\mu}{\sigma}=\frac{31-25}{\sqrt{36}}\]

Answer 2

thank you tons!

Answer 3

You're welcome :)