Jimmy's Chocolate shop sells two different fudge bars. The dark chocolate fudge bars sell for $5 per pound and the milk chocolate fudge bars sell for $4 per pound. You purchased a combination of these bars for your family and friends and your bill came to $150. This scenario can be modeled by the equation 5d + 4m = 150. Which of the following is not a possible combination of dark chocolate fudge bars and milk chocolate fudge bars?

6 dark bars and 30 milk bars
10 dark bars and 25 milk bars
12 dark bars and 23 milk bars
14 dark bars and 20 milk bars

Question

Jimmy's Chocolate shop sells two different fudge bars. The dark chocolate fudge bars sell for $5 per pound and the milk chocolate fudge bars sell for $4 per pound. You purchased a combination of these bars for your family and friends and your bill came to $150. This scenario can be modeled by the equation 5d + 4m = 150. Which of the following is not a possible combination of dark chocolate fudge bars and milk chocolate fudge bars? 

6 dark bars and 30 milk bars
10 dark bars and 25 milk bars
12 dark bars and 23 milk bars
14 dark bars and 20 milk bars

anonymous · Answer

plug in the values for m and d and see if the equation is valid
ex. 5(6)+4(30)=150
30+120=150
150=150 so this is true and 5 dark and 30 milk is possible