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Trigonometry
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cosxsinx+ sinx=0
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\[=\sin(x)(\cos(x)+1)=0 \implies \sin(x)=0; \cos(x)=-1\]\[\implies x = n \pi; x=(2m+1) \pi \] But since n pi includes all the (2m+1)'s, I think you can just write it as n pi.
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