Question

Solve the given equation and round to the nearest 4 decimals
8^2x=11

please help me :c

Answer 1

\[8^{2x}=11\]

Answer 2

?

Answer 3

yes

Answer 4

Take log base 8 of both sides

\[\log _{8}(8^{2x})=\log _{8}(11)\]

Answer 5

the left parts cancel out and leaves

\[2x=\log_{8}(11)\]

Answer 6

Then divide by 2 to get

\[x=\log_{8}(11)/2\]

Answer 7

ohhh thank you :D

Answer 8

Yep. Just type that into a calculator to get the actual number