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Mathematics 10 Online
OpenStudy (anonymous):

If 3-2i is a solution for x^2+bx+c=0, where b and c are real numbers, what is the value of b?

OpenStudy (anonymous):

Since 3 - 2i is a solution, to get real coefficients, 3 + 2i is also a solution. So, multiply out [x - (3 - 2i)][x - (3 + 2i)] = 0 to get form ax^2 + bx + c = 0

OpenStudy (anonymous):

Ok I will thank you!

OpenStudy (anonymous):

uw! Just hit "best response"

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