Question

HELP HELP HELP!!!!! (-3/5, 2) is a point on the terminal side of theta, find the value of the six trig functions

Answer 1

We apply Pythagoras to find "h"

Answer 2

(-3/5)^2 + 2^2 = h^2
9/25 + 4 = h^2
109/25 = h^2
h = sqrt(109) / 5

Answer 3

now we find trig functions:

sin