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I need to refresh my memory :/ How would I graph y=(x+3)^2+1?
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this is turning point form so the vertex is given
First of all you need to simplify the equation :)
Then you start assigning values for x and get y or assign for y and get x
And then just plot them up on a graph sheet :)
TP(-3,1) and the graphs intecepts can be seen when x=0 and when y=0
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