Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

Using the following equation: F = ma Solve for m.

OpenStudy (anonymous):

To solve for m, divide both sides by a, F/a=ma/a, so m = F/a.

OpenStudy (anonymous):

force = mass x acceleration

OpenStudy (anonymous):

hes right

OpenStudy (anonymous):

Divide by 'a' on both sides F/a = m

OpenStudy (anonymous):

Solve for H: V=LWH

OpenStudy (skullpatrol):

As long as a is not equal to 0.

OpenStudy (anonymous):

v = l*w*h v / (l*w) = (l*w*h) / (l*w) v /(l*w) = h h = v / (l*w) When you divide the circumference of a circle by its diameter you always get the same number. This number is called pi and it is 22 / 7 or 3.14. A = pi*r^2 is the formula that is used to find the area of a circle given its dimeter/radius.

OpenStudy (anonymous):

During an experiment that Paul and Dawn performed, the stretch of a spring was directly proportional to the force applied to the spring. When they put the data on a graph they would expect to have what type of curve?

OpenStudy (anonymous):

Make a new thread @lima345

OpenStudy (anonymous):

Well, Force= (spring constant) X (displacement) The k value is a constant, so F=x So if I'm not mistaken, the graph should be a diagonal straight line because the force always equals the displacement of the spring. Make sense?

OpenStudy (anonymous):

Find the slope of the line containing the two points (1,-1) and (-5,-3).

OpenStudy (anonymous):

-7/2

OpenStudy (anonymous):

If X = 5 and Y =3, what does Z equal? 2X + 2Z = 10Y

OpenStudy (anonymous):

your not going to learn anything if i just give you the answers & post it in a new thread

OpenStudy (anonymous):

JUST HELP ME WITH THAT ONE

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!