Which of the following is the vertex of the quadratic equation y = 6x^2 – 24x + 32?

Question

anonymous · Answer

–2, –8)

(–2, 8)

(2, –8)

(2, 8)

anonymous · Answer

I Need Someone To Show Me How To Do This Problem

campbell_st · Answer

ok... need to do some factoring 

y = 6(x^2 - 4x)  + 32

can you complete the square for x^2 - 4x ..?

anonymous · Answer

@campbell_st  I Think I Can Can You Just Show Me How To Do It So I Can Get A Sense Of How To Do The Other Problems

campbell_st · Answer

ok... so find half of the middle term (-4/2) then square it

so you will have 

y = 6(x^2 - 4x + 4) + 32            

ehich means your original problem is now 

y = 6x^2 _24x + 24 + 8                     24 + 8 = 32   I just split the constant

so factoring you have

y = 6(x^2 - 4x + 4) + 8

or 

y = 6(x - 2)^2 + 8

the general form is 

y = (x - h)^2 + k

the vertex is at (h, k)

you need to identify the values of h and k... for the vertex in your question.