Question

g(x)= 6-x^2 at x=-2
a) find the slope of the tangent
b) find the equation of the tangent line

So far I only have g(x)=6-x^2 and g'(x)=-2x

Answer 1

g'(x)=-2x
Replace x in the RHS with -2

Answer 2

\[g'(x)=-2x\\
a)\ g'(-2)=4\\
b)\ y-g(-2)=g'(-2)[x--2]\\
\ \ \ \ y-2=4[x+2]
\]

Answer 3

Thank you @robtobey and @oldrin.bataku ! I am having a lot of trouble with this section and appreciate the help!

Answer 4

@smc21 feel free to post any calculus questions you have.