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Calculus Q...please help :) A tank in the shape of an inverted right circular cone has height 6 meters and radius 3 meters. It is filled with 4 meters of hot chocolate. Find the work required to empty the tank by pumping the hot chocolate over the top of the tank. The density of hot chocolate is = 1020 kg/m^3.
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If we divide the cone up into thin discs of thickness dh then the volume of the thin disc is π(3h/6)²dh and the mass is 1020π(3h/6)²dh Now integrating mgh from h = 2 to 11 we get: ∫1020π(3h/6)² * 9.8 * h dh so what's next???
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