Question

solve for x in the given interval
sinxtan3x=0(-pi,0)

Answer 1

given sinx tan3x=0
means either sinx=0 or tan3x=0
if sinx=0 then x=n(pi) where n is an integer
if tan3x=0 then 3x=m(pi) where m is an integer
for getting the values in the given inter use proper values for n and m
and thus the answer are 0.-(pi)/3,-2(pi)/3,-pi etc..

Answer 2

how is -2pi/3 in the interval?

Answer 3

when m=2 in 3x=mpi and it is less than -pi
also tan3(-2(pi)/3))=0