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The sum of the first n odd whole numbers is equal to ___.
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1 + 3 + 5 + 7.......... nSo...u See it is a AP with D=2 Find its Sum
this can be done by applying A.P
a = 1 and d=2 so put formula\[n/2 [2a + (n-1)d]\]
n/2 [2(1) + (n-1)2] n/2 [2+ 2n -2] n/2 multiplied by 2n so the answer is \[n^2\]
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