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Determine the equation of the line tangent to the graph of y=15e^((6x)^2)- 6x at x=2 in the form t=mx+b
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first find the derivative of the function
f'(2)=m for your tangent line equation. You will also need a point on your line to fully describe it. We know the line goes through the point (2, f(2)). So your line will be described by:\[y-f(2)=f'(2)(x-2)\]rearrange into standard form and you're done :)
let me know if you get stuck...I'll be online later
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