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Use right triangles to solve cos(arcsin (12/13) + arccos (8/12)
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well you need to draw some triangles |dw:1353525302945:dw| next, again you will need to find the missing side so you can find sin(b) |dw:1353525430334:dw| Now I'm not really sure or the expression... is it \[\cos[\arcsin(12/13) + \arccos(8/12)]\] if it is then you will need to use the expansion of cos(A +B)
yes that is the expression but how do you use (a+b)
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