Question

f(x)=x^3-7x+6 find the rational zeros.

Answer 1

Well by inspection you can see that 1 is a solution 1-7+6=0 so:
\[x^3-7x+6=(x-1)(x^2+x-6)=(x-1)(x+3)(x-2)=0 \]
\[\implies x=1,2,-3\]