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Find the solutions to the function, f(x), below, when f(x)=0.
See where it cross the x axis and then make the equation by multiplying out x
2&3?
and...
-1
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therefore you have the equation y=(x+1)(x-2)(x-3) and then you multiply it out to get: y=x^3-4x^2+x-6
all true, but questions only asks for solutions to \(f(x)=0\) and those are what you said \(-1,2,3\)
Oh :/ sorry, ignore me then lol
lol, thank you both SO my answer would be f(x)=0 Answer: -1,2,3?
Yep :)
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thank you (:
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