Question

the perimeter of a rectangle is 54 m and the area of the rectangle is 72m^2. find the dimensions of the rectangle

Answer 1

rectangle or square?

Answer 2

if rectangle
A=l*w
54=2l+2w
If square
A=s^2
54=s*4

Depending on whether square or rectangle solve the system of equation. BUt i bet it is square.

Answer 3

13.5 sides if a square

Answer 4

It's not a square, since 13.5^2 != 72 (which was the area)

The area of a rectangle is given by w * l, the perimeter is 2w + 2l as timo already said.

The area of our rectangle is 72, and the perimeter is 54, so:
w * l = 72
2w + 2l = 54

All you have to do is solve the system of equations to get the width and length of the rectangle (hint: solve for w in one equation, and substitute it into the other one)

Answer 5

i did it wrong i forgot to plug in the area