Question

what is the vertex form for:y=1/3x^2 + 5/3x ?

Answer 1

\[y=\frac{1}{3}(x^2+5x)\]
\[y=\frac{1}{3}(x+\frac{5}{2})^2+k\] to find \(k\) replace \(x\) by \(-\frac{5}{2}\) in the original expresson

Answer 2

you should get
\[y=\frac{1}{3}(x+\frac{5}{2})^2-\frac{25}{12}\]