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(76 x 76 x 76 + 63 x 63 x 63) / (76 x 76 + 63 x 63 - 76 x 63) can we calculate the result without calculate each term ( I mean without finding 76 x 76 x 76 )
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yes.
how?
\(\large a^3+b^3 = (a+b)(a^2-ab+b^2)\)
a+b= ?
then put a= 76,b=63
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got that ^ ?
yes..., got it..., :D thanks a lot...
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