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Mathematics 9 Online
OpenStudy (anonymous):

find dy/dx if y+sinxy=x

hartnn (hartnn):

have u tried this ?or know how to start ?

OpenStudy (anonymous):

u must use implicit differentiation

hartnn (hartnn):

u need both , chain rule and product rule.

OpenStudy (anonymous):

dy/dx + cos(xy)*y*x*dy/dx=1 dy/dx(1+cos(xy)*y*x)=1 common factor taken dy/dx=1/(1.cos(xy)*x*y)

OpenStudy (anonymous):

my medal please,n by the way hartnn u r ryt.

OpenStudy (anonymous):

dy/dx=(1-ycos(xy))/(1+xcos(xy))

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