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What is the slope of a line that passes through 2,12 and -1,3 Hint: think rise over run
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2= x1 12=y1 -1=x2 3=y2 \[\frac{ y2-y1 }{ x2-x1 } \]
(3-12)/(-1-2)=-9/-3=3 slope=(y2-y1)/(x2-x1)
\[\frac{ 3-12 }{ -1-2 }\]
\[\frac{ -9 }{ -3 }\] = \[\frac{ 9 }{ 3 } = 3\]
Therefore, the slope equals 3.
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