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OpenStudy (anonymous):
\[y=5(x+3)^2-36\]
OpenStudy (anonymous):
@hba ?
OpenStudy (hba):
Sure...
OpenStudy (hba):
The vertex form is represented as
\[ y= a(x-h)²+k\]
OpenStudy (hba):
Lets see your question
\[y=5(x+3)^2-36\]
we know that (a+b)^2 = a^2+2ab+b^2
Now Please Use this formula and tell me what you get ?
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OpenStudy (anonymous):
sure, just a minute
OpenStudy (hba):
Your standard form will look like,
\[y = ax² + bx + c\]
OpenStudy (anonymous):
I don't have a b?
OpenStudy (hba):
Just show me what you got ?
OpenStudy (shaik0124):
if u solve u will get b
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OpenStudy (anonymous):
solving now
OpenStudy (hba):
ok
OpenStudy (shaik0124):
solve
OpenStudy (anonymous):
i got 0 = 10b... @_@ maybe i did something wrong
OpenStudy (shaik0124):
abba what emmah u did:P
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OpenStudy (hba):
Lets see your question
y=5(x+3)^2−36
we know that (a+b)^2 = a^2+2ab+b^2
Now Please Use this formula and tell me what you get ?
Just do this step and tell me.
OpenStudy (hba):
Just apply the formula.....
OpenStudy (anonymous):
I got 0 = 10b, or b=0.....
OpenStudy (hba):
No let me show you wait
OpenStudy (anonymous):
okay
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OpenStudy (shaik0124):
just use ur mind emmah hba wait she will try
OpenStudy (hba):
Just consider your question is (x+3)^2
according to formula (a+b)^2=a^2+2ab+b^2
here a =x and b=3 now just replace them
OpenStudy (shaik0124):
can i say answer hba
OpenStudy (hba):
noooo
OpenStudy (shaik0124):
atleast she gets clarity
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OpenStudy (anonymous):
don't say the answer, if i don't try i'll never get it lol
OpenStudy (hba):
Just try what i told you to do.
OpenStudy (anonymous):
okay
OpenStudy (hba):
Because you are not good with basic algebra.
OpenStudy (hba):
Maybe i can put down a tutorial later on for you.
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OpenStudy (shaik0124):
sh is good but mind is diverted now
OpenStudy (hba):
If you have time.
OpenStudy (anonymous):
I am good with basic algebra... i just don't understand what you're saying. I can do standard form to vertex form perfectly, but this is a little bit harder for me
OpenStudy (hba):
You don't know how to apply a formula ?
OpenStudy (anonymous):
sigh...
no, i applied the formula and it worked out. a = 5 and b = 3
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OpenStudy (hba):
Let me show you an example
(x+4)^2=x^2+2(x)(4)+4^2
=x^2+8x+16
OpenStudy (hba):
Now just apply (x+3)^2
OpenStudy (hba):
@shaik0124 Yaar tum iss ko ye solve karne do phir is equation mai dalwa daina.
OpenStudy (hba):
Samjhe ?
OpenStudy (shaik0124):
x^2+6x+9 u will get hba right
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OpenStudy (hba):
Direct answer mat daina warna ban krdunga @shaik0124
OpenStudy (anonymous):
(x+3)^2 = 64
OpenStudy (shaik0124):
ok
OpenStudy (shaik0124):
YAAR BAN KAISE KARTHE HAIN
OpenStudy (anonymous):
?_?
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OpenStudy (hba):
@Emmy82650 I got (x+4)^2=x^2+8x+167
and you got (x+3)^2=64 , Are you serious ?
OpenStudy (shaik0124):
HAHA
OpenStudy (anonymous):
.... Well, i think we're done here.
OpenStudy (hba):
@Emmy82650 If you can come here after 2 hours i am putting down a tutorial for you,understood.
OpenStudy (anonymous):
no thank you
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OpenStudy (hba):
Maths is the easiest subject and you are failing badly to understand.
OpenStudy (hba):
My tutorials are for all so even if you don't want it others will benefit.
OpenStudy (anonymous):
i will find another way to learn it. I don't feel like dealing with rude people at the moment. and yes, i understand math. I am taking am algebra 2 gifted honors course
OpenStudy (shaik0124):
emmah can i help u
OpenStudy (anonymous):
no thank you..
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