Solve the system by substitution.
2x+y=-11
3x-4y=11

A.(3, 5)
B.(–5, –3)
C.(–3, –5)
D.(5, 3)

Question

Solve the system by substitution.
2x+y=-11
3x-4y=11

A.(3, 5)
B.(–5, –3)
C.(–3, –5)
D.(5, 3)

noseboy908 · Answer

first pick what you want so solve for. (get a variable alone on one side)

anonymous · Answer

2x+y=-11 
3x-4y=11
------------

solve
2x+y=-11 for y

anonymous · Answer

2x+y=-11      (1)  6+5=11 you have -11        (1)  -10-3=-13 not -11
                =>A.                                        =>B
3x-4y=11             
                                            (1)=>-6-5=-11
A.(3, 5)                     =>C, (2)=>-9=20=11
B.(–5, –3)
C.(–3, –5)                       (1)=> 10+3=13 you have -11
D.(5, 3)                    =>D

so only C is right?