Question

ABC is an isosceles triangle, with AB=AC. AC=14cm. BC=10cm. Find the angle CBA.

Answer 1

use the law of cosines to find CBA



\[\cos(B) = \frac{a^2 + c^2 - b^2}{2ac}\]

Answer 2

This is what the question looks like.

Answer 3

do you know the law of cosines?

Answer 4

you can also use the fact that this is an isosceles triangle:
cosB = 5/14