Question

related rates

Answer 1

A and B are walking on straight streets that meet at right angles.A approaches the intersection at 2 m/sec ; B moves away from theintersection 1 m/sec. At what rate is the angle theta changing whenA is 10 m from the intersection and B is 20 m form theintersection? Express your answer in degrees per second in thenearest degree.

Answer 2

what i did is

Answer 3

\[\theta=\tan^{-1} (A/B)\]

Answer 4

\[d \theta/dt=\left(\begin{matrix} 1\\(A/B)^2+1\end{matrix}\right)dA/dt dB/dt\]